Functions to remove duplicates from a list.

Performance

To check the performance there was done a bunch of benchmarks. Benchmarks were made on lists of Ints and Texts. There were two types of list to use:

• Lists which consist of many different elements
• Lists which consist of many same elements

Here are some recommendations for usage of particular functions based on benchmarking results.

• hashNub is faster than ordNub when there're not so many different values in the list.
• hashNub is the fastest with Text.
• intNub is faster when you work with lists of Ints.
• intNubOn is fast with the lists of type that can have fixed number representations.
• sortNub has better performance than ordNub but should be used when sorting is also needed.
• unstableNub has better performance than hashNub but doesn't save the original order.

Like nub but runs in <math> time and requires Hashable.

>>> hashNub [3, 3, 3, 2, 2, -1, 1]
[3,2,-1,1]

Removes duplicate elements from a list, keeping only the first occurance of the element. Like nub but runs in <math> time and requires Ord.

>>> intNub [3, 3, 3, 2, 2, -1, 1]
[3,2,-1,1]

Similar to intNub but works on lists of any types by performing "nubbing" through Ints.

>>> intNubOn fromEnum "ababbbcdaffee"
"abcdfe"

Removes duplicate elements from a list, keeping only the first occurrence of the element. Like nub but runs in <math> time and requires Ord.

>>> ordNub [3, 3, 3, 2, 2, -1, 1]
[3,2,-1,1]

Similar to ordNub but performs nub through the mapped list on the given function.

>>> ordNubOn (`div` 10) [3, 3, 3, 13, 2, 22, -1, 1, 66]
[3,13,22,-1,66]

Like ordNub runs in <math> but also sorts a list.

>>> sortNub [3, 3, 3, 2, 2, -1, 1]
[-1,1,2,3]

Like hashNub runs in <math> but has better performance; it doesn't save the order.

>>> unstableNub [3, 3, 3, 2, 2, -1, 1]
[1,2,3,-1]